3.2503 \(\int \frac {(2+3 x)^3}{\sqrt [3]{28+54 x+27 x^2}} \, dx\)

Optimal. Leaf size=589 \[ \frac {1}{30} \left (27 x^2+54 x+28\right )^{2/3} (3 x+2)^2-\frac {1}{35} (8 x+1) \left (27 x^2+54 x+28\right )^{2/3}+\frac {4 \left (6-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right ) \sqrt {\frac {\left (27 x^2+54 x+28\right )^{2/3}+\sqrt [3]{27 x^2+54 x+28}+1}{\left (6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right )^2}} F\left (\sin ^{-1}\left (\frac {6 \left (1+\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}}{6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}}\right )|-7+4 \sqrt {3}\right )}{63\ 3^{3/4} (x+1) \sqrt {-\frac {6-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}}{\left (6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right )^2}}}-\frac {\sqrt {2 \left (2+\sqrt {3}\right )} \left (6-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right ) \sqrt {\frac {\left (27 x^2+54 x+28\right )^{2/3}+\sqrt [3]{27 x^2+54 x+28}+1}{\left (6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right )^2}} E\left (\sin ^{-1}\left (\frac {6 \left (1+\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}}{6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}}\right )|-7+4 \sqrt {3}\right )}{63 \sqrt [4]{3} (x+1) \sqrt {-\frac {6-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}}{\left (6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right )^2}}}+\frac {72 (x+1)}{7 \left (6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right )} \]

[Out]

1/30*(2+3*x)^2*(27*x^2+54*x+28)^(2/3)-1/35*(1+8*x)*(27*x^2+54*x+28)^(2/3)+72/7*(1+x)/(-2^(1/3)*(108+(54+54*x)^
2)^(1/3)+6-6*3^(1/2))+4/189*(6-2^(1/3)*(108+(54+54*x)^2)^(1/3))*EllipticF((-2^(1/3)*(108+(54+54*x)^2)^(1/3)+6+
6*3^(1/2))/(-2^(1/3)*(108+(54+54*x)^2)^(1/3)+6-6*3^(1/2)),2*I-I*3^(1/2))*((1+(27*x^2+54*x+28)^(1/3)+(27*x^2+54
*x+28)^(2/3))/(-2^(1/3)*(108+(54+54*x)^2)^(1/3)+6-6*3^(1/2))^2)^(1/2)*3^(1/4)/(1+x)/((-6+2^(1/3)*(108+(54+54*x
)^2)^(1/3))/(-2^(1/3)*(108+(54+54*x)^2)^(1/3)+6-6*3^(1/2))^2)^(1/2)-1/189*(6-2^(1/3)*(108+(54+54*x)^2)^(1/3))*
EllipticE((-2^(1/3)*(108+(54+54*x)^2)^(1/3)+6+6*3^(1/2))/(-2^(1/3)*(108+(54+54*x)^2)^(1/3)+6-6*3^(1/2)),2*I-I*
3^(1/2))*((1+(27*x^2+54*x+28)^(1/3)+(27*x^2+54*x+28)^(2/3))/(-2^(1/3)*(108+(54+54*x)^2)^(1/3)+6-6*3^(1/2))^2)^
(1/2)*(1+3^(1/2))*3^(3/4)/(1+x)/((-6+2^(1/3)*(108+(54+54*x)^2)^(1/3))/(-2^(1/3)*(108+(54+54*x)^2)^(1/3)+6-6*3^
(1/2))^2)^(1/2)

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Rubi [A]  time = 0.56, antiderivative size = 589, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.318, Rules used = {742, 779, 619, 235, 304, 219, 1879} \[ \frac {1}{30} \left (27 x^2+54 x+28\right )^{2/3} (3 x+2)^2-\frac {1}{35} (8 x+1) \left (27 x^2+54 x+28\right )^{2/3}+\frac {4 \left (6-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right ) \sqrt {\frac {\left (27 x^2+54 x+28\right )^{2/3}+\sqrt [3]{27 x^2+54 x+28}+1}{\left (6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right )^2}} F\left (\sin ^{-1}\left (\frac {6 \left (1+\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}}{6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}}\right )|-7+4 \sqrt {3}\right )}{63\ 3^{3/4} (x+1) \sqrt {-\frac {6-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}}{\left (6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right )^2}}}-\frac {\sqrt {2 \left (2+\sqrt {3}\right )} \left (6-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right ) \sqrt {\frac {\left (27 x^2+54 x+28\right )^{2/3}+\sqrt [3]{27 x^2+54 x+28}+1}{\left (6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right )^2}} E\left (\sin ^{-1}\left (\frac {6 \left (1+\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}}{6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}}\right )|-7+4 \sqrt {3}\right )}{63 \sqrt [4]{3} (x+1) \sqrt {-\frac {6-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}}{\left (6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right )^2}}}+\frac {72 (x+1)}{7 \left (6 \left (1-\sqrt {3}\right )-\sqrt [3]{2} \sqrt [3]{(54 x+54)^2+108}\right )} \]

Antiderivative was successfully verified.

[In]

Int[(2 + 3*x)^3/(28 + 54*x + 27*x^2)^(1/3),x]

[Out]

((2 + 3*x)^2*(28 + 54*x + 27*x^2)^(2/3))/30 - ((1 + 8*x)*(28 + 54*x + 27*x^2)^(2/3))/35 + (72*(1 + x))/(7*(6*(
1 - Sqrt[3]) - 2^(1/3)*(108 + (54 + 54*x)^2)^(1/3))) - (Sqrt[2*(2 + Sqrt[3])]*(6 - 2^(1/3)*(108 + (54 + 54*x)^
2)^(1/3))*Sqrt[(1 + (28 + 54*x + 27*x^2)^(1/3) + (28 + 54*x + 27*x^2)^(2/3))/(6*(1 - Sqrt[3]) - 2^(1/3)*(108 +
(54 + 54*x)^2)^(1/3))^2]*EllipticE[ArcSin[(6*(1 + Sqrt[3]) - 2^(1/3)*(108 + (54 + 54*x)^2)^(1/3))/(6*(1 - Sqr
t[3]) - 2^(1/3)*(108 + (54 + 54*x)^2)^(1/3))], -7 + 4*Sqrt[3]])/(63*3^(1/4)*(1 + x)*Sqrt[-((6 - 2^(1/3)*(108 +
(54 + 54*x)^2)^(1/3))/(6*(1 - Sqrt[3]) - 2^(1/3)*(108 + (54 + 54*x)^2)^(1/3))^2)]) + (4*(6 - 2^(1/3)*(108 + (
54 + 54*x)^2)^(1/3))*Sqrt[(1 + (28 + 54*x + 27*x^2)^(1/3) + (28 + 54*x + 27*x^2)^(2/3))/(6*(1 - Sqrt[3]) - 2^(
1/3)*(108 + (54 + 54*x)^2)^(1/3))^2]*EllipticF[ArcSin[(6*(1 + Sqrt[3]) - 2^(1/3)*(108 + (54 + 54*x)^2)^(1/3))/
(6*(1 - Sqrt[3]) - 2^(1/3)*(108 + (54 + 54*x)^2)^(1/3))], -7 + 4*Sqrt[3]])/(63*3^(3/4)*(1 + x)*Sqrt[-((6 - 2^(
1/3)*(108 + (54 + 54*x)^2)^(1/3))/(6*(1 - Sqrt[3]) - 2^(1/3)*(108 + (54 + 54*x)^2)^(1/3))^2)])

Rule 219

Int[1/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, Simp[(2*Sqr
t[2 - Sqrt[3]]*(s + r*x)*Sqrt[(s^2 - r*s*x + r^2*x^2)/((1 - Sqrt[3])*s + r*x)^2]*EllipticF[ArcSin[((1 + Sqrt[3
])*s + r*x)/((1 - Sqrt[3])*s + r*x)], -7 + 4*Sqrt[3]])/(3^(1/4)*r*Sqrt[a + b*x^3]*Sqrt[-((s*(s + r*x))/((1 - S
qrt[3])*s + r*x)^2)]), x]] /; FreeQ[{a, b}, x] && NegQ[a]

Rule 235

Int[((a_) + (b_.)*(x_)^2)^(-1/3), x_Symbol] :> Dist[(3*Sqrt[b*x^2])/(2*b*x), Subst[Int[x/Sqrt[-a + x^3], x], x
, (a + b*x^2)^(1/3)], x] /; FreeQ[{a, b}, x]

Rule 304

Int[(x_)/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Rt[b/a, 3]], s = Denom[Rt[b/a, 3]]}, -Dist[(S
qrt[2]*s)/(Sqrt[2 - Sqrt[3]]*r), Int[1/Sqrt[a + b*x^3], x], x] + Dist[1/r, Int[((1 + Sqrt[3])*s + r*x)/Sqrt[a
+ b*x^3], x], x]] /; FreeQ[{a, b}, x] && NegQ[a]

Rule 619

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Dist[1/(2*c*((-4*c)/(b^2 - 4*a*c))^p), Subst[Int[Si
mp[1 - x^2/(b^2 - 4*a*c), x]^p, x], x, b + 2*c*x], x] /; FreeQ[{a, b, c, p}, x] && GtQ[4*a - b^2/c, 0]

Rule 742

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(e*(d + e*x)^(m - 1)
*(a + b*x + c*x^2)^(p + 1))/(c*(m + 2*p + 1)), x] + Dist[1/(c*(m + 2*p + 1)), Int[(d + e*x)^(m - 2)*Simp[c*d^2
*(m + 2*p + 1) - e*(a*e*(m - 1) + b*d*(p + 1)) + e*(2*c*d - b*e)*(m + p)*x, x]*(a + b*x + c*x^2)^p, x], x] /;
FreeQ[{a, b, c, d, e, m, p}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && NeQ[2*c*d - b*e, 0]
&& If[RationalQ[m], GtQ[m, 1], SumSimplerQ[m, -2]] && NeQ[m + 2*p + 1, 0] && IntQuadraticQ[a, b, c, d, e, m,
p, x]

Rule 779

Int[((d_.) + (e_.)*(x_))*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> -Simp[((b
*e*g*(p + 2) - c*(e*f + d*g)*(2*p + 3) - 2*c*e*g*(p + 1)*x)*(a + b*x + c*x^2)^(p + 1))/(2*c^2*(p + 1)*(2*p + 3
)), x] + Dist[(b^2*e*g*(p + 2) - 2*a*c*e*g + c*(2*c*d*f - b*(e*f + d*g))*(2*p + 3))/(2*c^2*(2*p + 3)), Int[(a
+ b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] && NeQ[b^2 - 4*a*c, 0] &&  !LeQ[p, -1]

Rule 1879

Int[((c_) + (d_.)*(x_))/Sqrt[(a_) + (b_.)*(x_)^3], x_Symbol] :> With[{r = Numer[Simplify[((1 + Sqrt[3])*d)/c]]
, s = Denom[Simplify[((1 + Sqrt[3])*d)/c]]}, Simp[(2*d*s^3*Sqrt[a + b*x^3])/(a*r^2*((1 - Sqrt[3])*s + r*x)), x
] + Simp[(3^(1/4)*Sqrt[2 + Sqrt[3]]*d*s*(s + r*x)*Sqrt[(s^2 - r*s*x + r^2*x^2)/((1 - Sqrt[3])*s + r*x)^2]*Elli
pticE[ArcSin[((1 + Sqrt[3])*s + r*x)/((1 - Sqrt[3])*s + r*x)], -7 + 4*Sqrt[3]])/(r^2*Sqrt[a + b*x^3]*Sqrt[-((s
*(s + r*x))/((1 - Sqrt[3])*s + r*x)^2)]), x]] /; FreeQ[{a, b, c, d}, x] && NegQ[a] && EqQ[b*c^3 - 2*(5 + 3*Sqr
t[3])*a*d^3, 0]

Rubi steps

\begin {align*} \int \frac {(2+3 x)^3}{\sqrt [3]{28+54 x+27 x^2}} \, dx &=\frac {1}{30} (2+3 x)^2 \left (28+54 x+27 x^2\right )^{2/3}+\frac {1}{90} \int \frac {(-360-432 x) (2+3 x)}{\sqrt [3]{28+54 x+27 x^2}} \, dx\\ &=\frac {1}{30} (2+3 x)^2 \left (28+54 x+27 x^2\right )^{2/3}-\frac {1}{35} (1+8 x) \left (28+54 x+27 x^2\right )^{2/3}-\frac {4}{7} \int \frac {1}{\sqrt [3]{28+54 x+27 x^2}} \, dx\\ &=\frac {1}{30} (2+3 x)^2 \left (28+54 x+27 x^2\right )^{2/3}-\frac {1}{35} (1+8 x) \left (28+54 x+27 x^2\right )^{2/3}-\frac {2}{189} \operatorname {Subst}\left (\int \frac {1}{\sqrt [3]{1+\frac {x^2}{108}}} \, dx,x,54+54 x\right )\\ &=\frac {1}{30} (2+3 x)^2 \left (28+54 x+27 x^2\right )^{2/3}-\frac {1}{35} (1+8 x) \left (28+54 x+27 x^2\right )^{2/3}-\frac {\left (2 \sqrt {(54+54 x)^2}\right ) \operatorname {Subst}\left (\int \frac {x}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{28+54 x+27 x^2}\right )}{7 \sqrt {3} (54+54 x)}\\ &=\frac {1}{30} (2+3 x)^2 \left (28+54 x+27 x^2\right )^{2/3}-\frac {1}{35} (1+8 x) \left (28+54 x+27 x^2\right )^{2/3}+\frac {\left (2 \sqrt {(54+54 x)^2}\right ) \operatorname {Subst}\left (\int \frac {1+\sqrt {3}-x}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{28+54 x+27 x^2}\right )}{7 \sqrt {3} (54+54 x)}-\frac {\left (2 \sqrt {\frac {2}{3} \left (2+\sqrt {3}\right )} \sqrt {(54+54 x)^2}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {-1+x^3}} \, dx,x,\sqrt [3]{28+54 x+27 x^2}\right )}{7 (54+54 x)}\\ &=\frac {1}{30} (2+3 x)^2 \left (28+54 x+27 x^2\right )^{2/3}-\frac {1}{35} (1+8 x) \left (28+54 x+27 x^2\right )^{2/3}+\frac {12 (1+x)}{7 \left (1-\sqrt {3}-\sqrt [3]{28+54 x+27 x^2}\right )}-\frac {2 \sqrt {2+\sqrt {3}} \left (1-\sqrt [3]{28+54 x+27 x^2}\right ) \sqrt {\frac {1+\sqrt [3]{28+54 x+27 x^2}+\left (28+54 x+27 x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{28+54 x+27 x^2}\right )^2}} E\left (\sin ^{-1}\left (\frac {1+\sqrt {3}-\sqrt [3]{28+54 x+27 x^2}}{1-\sqrt {3}-\sqrt [3]{28+54 x+27 x^2}}\right )|-7+4 \sqrt {3}\right )}{21\ 3^{3/4} (1+x) \sqrt {-\frac {1-\sqrt [3]{28+54 x+27 x^2}}{\left (1-\sqrt {3}-\sqrt [3]{28+54 x+27 x^2}\right )^2}}}+\frac {4 \sqrt {2} \left (1-\sqrt [3]{28+54 x+27 x^2}\right ) \sqrt {\frac {1+\sqrt [3]{28+54 x+27 x^2}+\left (28+54 x+27 x^2\right )^{2/3}}{\left (1-\sqrt {3}-\sqrt [3]{28+54 x+27 x^2}\right )^2}} F\left (\sin ^{-1}\left (\frac {1+\sqrt {3}-\sqrt [3]{28+54 x+27 x^2}}{1-\sqrt {3}-\sqrt [3]{28+54 x+27 x^2}}\right )|-7+4 \sqrt {3}\right )}{63 \sqrt [4]{3} (1+x) \sqrt {-\frac {1-\sqrt [3]{28+54 x+27 x^2}}{\left (1-\sqrt {3}-\sqrt [3]{28+54 x+27 x^2}\right )^2}}}\\ \end {align*}

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Mathematica [C]  time = 0.03, size = 53, normalized size = 0.09 \[ \frac {1}{210} \left (27 x^2+54 x+28\right )^{2/3} \left (63 x^2+36 x+22\right )-\frac {4}{7} (x+1) \, _2F_1\left (\frac {1}{3},\frac {1}{2};\frac {3}{2};-27 (x+1)^2\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[(2 + 3*x)^3/(28 + 54*x + 27*x^2)^(1/3),x]

[Out]

((28 + 54*x + 27*x^2)^(2/3)*(22 + 36*x + 63*x^2))/210 - (4*(1 + x)*Hypergeometric2F1[1/3, 1/2, 3/2, -27*(1 + x
)^2])/7

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fricas [F]  time = 1.16, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8}{{\left (27 \, x^{2} + 54 \, x + 28\right )}^{\frac {1}{3}}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^3/(27*x^2+54*x+28)^(1/3),x, algorithm="fricas")

[Out]

integral((27*x^3 + 54*x^2 + 36*x + 8)/(27*x^2 + 54*x + 28)^(1/3), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (3 \, x + 2\right )}^{3}}{{\left (27 \, x^{2} + 54 \, x + 28\right )}^{\frac {1}{3}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^3/(27*x^2+54*x+28)^(1/3),x, algorithm="giac")

[Out]

integrate((3*x + 2)^3/(27*x^2 + 54*x + 28)^(1/3), x)

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maple [F]  time = 3.11, size = 0, normalized size = 0.00 \[ \int \frac {\left (3 x +2\right )^{3}}{\left (27 x^{2}+54 x +28\right )^{\frac {1}{3}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3*x+2)^3/(27*x^2+54*x+28)^(1/3),x)

[Out]

int((3*x+2)^3/(27*x^2+54*x+28)^(1/3),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (3 \, x + 2\right )}^{3}}{{\left (27 \, x^{2} + 54 \, x + 28\right )}^{\frac {1}{3}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^3/(27*x^2+54*x+28)^(1/3),x, algorithm="maxima")

[Out]

integrate((3*x + 2)^3/(27*x^2 + 54*x + 28)^(1/3), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (3\,x+2\right )}^3}{{\left (27\,x^2+54\,x+28\right )}^{1/3}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3*x + 2)^3/(54*x + 27*x^2 + 28)^(1/3),x)

[Out]

int((3*x + 2)^3/(54*x + 27*x^2 + 28)^(1/3), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (3 x + 2\right )^{3}}{\sqrt [3]{27 x^{2} + 54 x + 28}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)**3/(27*x**2+54*x+28)**(1/3),x)

[Out]

Integral((3*x + 2)**3/(27*x**2 + 54*x + 28)**(1/3), x)

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